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Hi, question about passing or failing checks: is the result dependant on the ratio of dice that pass or fail? 1 fails, 2 pass = pass. 2 fails, 1 pass = fail? The note at the bottom of the page says to use fewer dice as they're resolved collectively, but I'm not sure what that means. Thanks!

Hi!
Whenever you choose a Feature to make a Check attempt, you roll a number of dice equal to it's value. Then count all Passes and all Fails.

Example:
You need 2 Passes to clear an area.
You roll Prowess, which has a value of 5, so you roll 5 dice. You get 3 Passes, and two Fails = the room is cleared, that's for sure, since you got at least two Passes.

Now comes the Tally!
Passes: you two 5's and a 4; Fails: you got two 2's.
Start the Tally from the highest values: 5, 5, 4, 2, 2.

So it goes like this:
5: (Up your Features or choose new Items) x2.
4: (Decrease any Feature by one, or lose an item)
2: (Decrease any Feature by one) x2

 And... see if you're still alive and/or found anything good :)

Ah, that makes sense. Thank you! I'm impressed with how much game you were able to get onto 2 pages. It's a fun little dungeon dive!

Thank you very much!